“微信扫一扫”进入考试题库练习及模拟考试
参考答案:\(CD = AB\)证明:连接\(AD\),\(OD\),\(\because \)点\(B\)关于直线\(OM\)的对称点为\(D\),点\(A\)在射线\(OM\)上,\(\therefore AD = AB\),\(\angle OAD = \angle OAB\),\(\because \angle OAB + \angle OAC = 60^\circ \),\(\therefore \angle OAD + \angle OAC = 60^\circ \),即\(\angle DAC = 60^\circ \),在\(\vartriangle OAC\)中,\(\angle ACO = 180^\circ - \angle OAC - \angle AOC = 180^\circ - (60^\circ - \angle OAB) - 60^\circ = 60^\circ + \angle OAB\),又\(\because \angle ABC = \angle AOB + \angle OAB = 60^\circ + \angle OAB\),\(\therefore \angle ACO = \angle ABC\),\(\therefore AB = AC\),\(\therefore AC = AD\),又\(\because \angle CAD = 60^\circ \),\(\therefore \vartriangle ACD\)是等边三角形,\(\therefore CD = AD\),\(\therefore CD = AB\).
第243题
当
参考答案:
证明:如图,在
即
参考答案:①②
第247题
如图,∠ABC=60°,AB=3,动点P从点B出发,以1cm/s的速度沿射线BC运动,设点P的运动时间为t秒,当△ABP是钝角三角形时,t的取值范围是___。
参考答案:\(0 < t < 1.5或t > 6\)
第248题
如图,在
参考答案:11
第253题
计算:
A.\(\frac{4}{3}\)
B.\(\frac{3}{4}\)
C.\( - \frac{4}{3}\)
D.\( - \frac{3}{4}\)
参考答案:D
第256题
下列运算正确的是
A.\({(ab)^2} = {a^2}{b^2}\)
B.\({a^3} + {a^2} = {a^5}\)
C.\({a^3} \cdot {a^2} = {a^6}\)
D.\( (a+b{)}^{2}={a}^{2}+{b}^{2}\)
参考答案:A