“微信扫一扫”进入题库练习及模拟考试
先化简,再求值:
参考答案:原式=\( \frac{{x}^{4}{y}^{4}}{(x-y{)}^{8}}\cdot (x-y{)}^{3}\cdot \frac{{x}^{4}}{{y}^{10}}\cdot \frac{{y}^{5}(x-y{)}^{5}}{{x}^{5}}\)=\( \frac{{x}^{3}}{y}\),又因为\( x=-2\),\( y=4\),所以原式=\( \frac{{x}^{3}}{y}=\frac{{\left(-2\right)}^{3}}{4}=-2\)