“微信扫一扫”进入题库练习及模拟考试
已知∠AOB=30°,点P在∠AOB的内部,P1与P关于OA对称,P2与P关于OB对称,
判定
参考答案:\(\because {P_1}\)与\(P\)关于\(OB\)对称\(\therefore OP = O{P_1}\),\(\angle {P_1}OB = BOP\)\(\because {P_2}\)与\(P\)关于\(OA\)对称\(\therefore OP = O{P_2}\),\(\angle {P_2}OA = AOP\)\(\therefore O{P_1} = O{P_2}\),\(\angle {P_1}O{P_2} = 2\angle BOA = 60^\circ \)\(\therefore \)△\({P_1}O{P_2}\)为等边三角形