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如图,点O是等边
连接AC、AD。
当α=150°时,试判断
参考答案:由\(\Delta OCD\)和\(\Delta ABC\)是等边三角形,可证\(\Delta BOC \cong \Delta ADC\),进而得\(\angle BOC = \angle ADC\),所以\(\angle ADO = \angle ADC - \angle ODC = 150^\circ - 60^\circ = 90^\circ \),\(\Delta ADO\)是直角三角形。