“微信扫一扫”进入题库练习及模拟考试
如图,在
求证:

                        参考答案:证明:\(\because AB//ED\),\(\therefore \angle EAB = \angle E\),\(\because \angle DAB = \angle BAE + \angle B\),\(\angle DAB = \angle BAE + \angle DAE\),\(\therefore \angle B = \angle DAE\),在\(\Delta ABC\)和\(\Delta EAD\)中,\(\left\{ {\begin{array}{*{20}{l}}
  {\angle B = \angle DAE} \\ 
  {AB = EA} \\ 
  {\angle BAC = \angle E} 
\end{array}} \right.\),\(\therefore \Delta ABC \cong \Delta EAD(ASA)\),\(\therefore AC = ED\).