“微信扫一扫”进入题库练习及模拟考试
如图,点

求证:
                        参考答案:证明:正五边形\(ABCDE\)中,\(AB = BC\),\(\angle ABM = \angle C\),在\(\Delta ABM\)和\(\Delta BCN\)中\(\left\{ {\begin{array}{*{20}{l}}
  {AB = BC} \\ 
  {\angle ABM = \angle C} \\ 
  {BM = CN} 
\end{array}} \right.\),\(\therefore \Delta ABM \cong \Delta BCN(SAS)\);