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如图所示,点\(O\)是\(\Delta ABC\)内一点,\(BO\)平分\(\angle ABC\),\(OD \bot BC\)于点\(D\),连接\(OA\),若\(OD = 5\),\(AB = 20\),则\(\Delta AOB\)的面积是\((\) \()\)。
A.20
B.30
C.50
D.100
参考答案:C
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