“微信扫一扫”进入题库练习及模拟考试
如图:已知
参考答案:\(\because BF \bot AC\),\(CE \bot AB\),\(\therefore \angle BED = \angle CFD = 90^\circ \),在\(\Delta BED\)和\(\Delta CFD\)中,\(\left\{ {\begin{array}{*{20}{l}}
{\angle BED = \angle CFD} \\
{\angle BDE = \angle CDF} \\
{BD = CD}
\end{array}} \right.\),\(\therefore \Delta BED \cong \Delta CFD(AAS)\),\(\therefore DE = DF\),又\(\because DE \bot AB\),\(DF \bot AC\),\(\therefore \)点\(D\)在\(\angle BAC\)的平分线上.