β-0.2α
（1）\(\because EF//BC\)，\(\angle BEF = 120^\circ \)，
\(\therefore \angle EBC = 60^\circ \)，\(\angle AEF = 60^\circ \)，
又\(\because BD\)平分\(\angle EBC\)，
\(\therefore \angle EBD = \angle BDE = \angle DBC = 30^\circ \)，
又\(\because \angle BDA = 90^\circ \)，
\(\therefore \angle EDA = 60^\circ \)，
\(\therefore \angle BAD = 60^\circ \)；
（2）如图2，过点\(A\)作\(AG//BC\)，
则\(\angle BDA = \angle DBC + \angle DAG = \angle DBC + \angle FAD + \angle FAG = \angle DBC + \angle FAD + \angle C = \beta \)，
则\(\angle FAD + \angle C = \beta - \angle DBC = \beta - \frac{1}{2}\angle ABC = \beta - \frac{1}{2}\alpha \)．
