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下列方程的变形,符合等式性质的是( )
A.由\(4x + 2 = 3x\),得\(4x = 3x + 2\)
B.由\(\frac{y}{2} = 0\),得\(y = 2\)
C.由\(a = b\),得\(\frac{a}{{{c^2} + 1}} = \frac{b}{{{c^2} + 1}}\)
D.由\( - 7x = 5\),得\(x = \frac{5}{7}\)
参考答案:C
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