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若\({(2x - 1)^5} = {a_5}{x^5} + {a_4}{x^4} + {a_3}{x^3} + {a_2}{x^2} + {a_1}x + {a_0}\),试求:
当\(x = 1\)时,有何结论?
参考答案:当\(x = 1\)时,\({(2 - 1)^5} = {a_5} + {a_4} + {a_3} + {a_2} + {a_1} + {a_0}\),即\({a_0} + {a_1} + {a_2} + {a_3} + {a_4} + {a_5} = 1\)①;
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