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已知\({a^2} = 16\)，\(|b| = 2\)，且\(a > b\)，\(a + b\)的值为___．
参考答案：6或2
解析：
解：\(\because {a^2} = 16\)，\(\therefore a = \pm 4\)，
\(\because |b| = 2\)，\(\therefore b = \pm 2\)，
又\(\because a > b\)，\(\therefore a = 4\)，\(b = 2\)或\(a = 4\)，\(b = - 2\)，
则\(a + b = 4 + 2 = 6\)，或\(a + b = 4 - 2 = 2\)．
故答案为：6或2．
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