高中数学选择性必修 第二册(381题)
\(y=\frac {1} {\sqrt {1-2{x}^{2}}}\)
知识点:第五章 一元函数的导数及其应用
参考答案:\({y}^{,}=\frac {2x} {\left ( {1-2{x}^{2}} \right )\sqrt {1-2{x}^{2}}}\)
解析:
\({y}^{,}=\left ( {\left ( {1-2{x}^{2}} \right )^{-\frac {1} {2}}} \right )^{\, '}=-\frac {1} {2}\left ( {1-2{x}^{2}} \right )^{-\frac {3} {2}}\left ( {-4x} \right )=\frac {2x} {\sqrt {\left ( {1-2{x}^{2}} \right )^{3}}}=\frac {2x} {\left ( {1-2{x}^{2}} \right )\sqrt {1-2{x}^{2}}}\)