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若数列\( \left\{2{a}_{n}+1\right\}\)是等差数列,其公差\( d=1\),且\({a_3} = 5\),则\( {a}_{10}=\)___.
参考答案:\( \frac{17}{2}\)
解析:
∵数列\( \left\{2{a}_{n}+1\right\}\)是等差数列,则\( \left(2{a}_{10}+1\right)=\left(2{a}_{3}+1\right)+7d=18\)
∴\( {a}_{10}=\frac{17}{2}\)
故答案为:\( \frac{17}{2}\).
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