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经过抛物线\(C:{x}^{2}=4y\)的焦点\(F\)的直线交此抛物线于\(A,B\)两点,抛物线在\(A,B\)两点处的切线相交于点\(M\),则点\(M\)所在的直线方程是( )
A.\(x = - 1\)
B.\(x = 1\)
C.\(y=-1\)
D.\(y = 1\)
参考答案:C
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