已知定圆\({F}_{1}:(x+5{)}^{2}+{y}^{2}=1\)，定圆\({F}_{2}:(x-5{)}^{2}+{y}^{2}=1\)，动圆\(M\

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已知定圆\({F}_{1}:(x+5{)}^{2}+{y}^{2}=1\)，定圆\({F}_{2}:(x-5{)}^{2}+{y}^{2}=1\)，动圆\(M\)与定圆\({F}_{1}\)，\({F}_{2}\)都外切，则动圆圆心\(M\)的轨迹方程为___.

参考答案：\(\frac {{x}^{2}} {\frac {9} {4}}-\frac {{y}^{2}} {\frac {91} {4}}=1(x\leq -\frac {3} {2})\)