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已知平面内两定点\(A(-5,0)\),\(B(5,0)\),动点\(M\)满足\(|MA|-|MB|=6\),则点\(M\)的轨迹方程是( )
A.\(\frac {{x}^{2}} {16}-\frac {{y}^{2}} {9}=1\)
B.\(\frac {{x}^{2}} {16}-\frac {{y}^{2}} {9}=1(x\geq 4)\)
C.\(\frac {{x}^{2}} {9}-\frac {{y}^{2}} {16}=1\)
D.\(\frac {{x}^{2}} {9}-\frac {{y}^{2}} {16}=1(x\geq 3)\)
参考答案:D
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