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若点\(A(a,b)\)在圆\({x}^{2}{+y}^{2}=4\)上,则圆\((x-a{)}^{2}+{y}^{2}=1\)与圆\({x}^{2}+(y-b{)}^{2}=1\)的位置关系是___.
参考答案:外切
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