已知圆\(C\)：\({x^2} + {y^2} - 4x - 14y + 45 = 0\)及点\(Q\left( {

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已知圆\(C\)：\({x^2} + {y^2} - 4x - 14y + 45 = 0\)及点\(Q\left( { - 2,3} \right)\)，则下列说法正确的是\( (\) \( )\).

A.点\(C\)的坐标为\(\left( {2,7} \right)\)

B.点\(Q\)在圆\(C\)外

C.若点\(P\left( {m,m + 1} \right)\)在圆\(C\)上，则直线\(PQ\)的斜率为\(\frac{1}{4}\)

D.若\(M\)是圆\(C\)上任一点，则\(\left| {MQ} \right|\)的取值范围为\(\left[ {2\sqrt 2 ,6\sqrt 2 } \right]\)

参考答案：ABD