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若复数\(z = ({a^2} - a - 6) + \frac{{a + 2}}{{2a - 1}}{\rm{i}}\)（\(a \in R\)）是纯虚数，求\({z_1} = (1 - 2a) + (a - 1){\rm{i}}\)的模.
参考答案：\(\sqrt {29}\)
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