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如图,在直角\(\Delta ABC\)中,点\(D\)为斜边\(BC\)的靠近点\(B\)的三等分点,点\(E\)为\(AD\)的中点,\(\left| {\overrightarrow {AB} } \right| = 3,\left| {\overrightarrow {AC} } \right| = 6\).
求向量\(\overrightarrow {EB} \)与\(\overrightarrow {EC} \)夹角的余弦值.
参考答案:\( - \frac{{7\sqrt {130} }}{{130}}\)
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