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如图,在菱形
当\(\angle BAD = 100^\circ \)时,求\(\angle EAF\)的度数。
参考答案:解:
\(\because \)四边形\(ABCD\)是菱形,
\(\therefore AD//BC\),
\(\therefore \angle BAD + \angle B = 180^\circ \),
\(\because \angle BAD = 100^\circ \),
\(\therefore \angle B = 80^\circ \)
\(\because AE \bot BC\),
\(\therefore \angle AEB = 90^\circ \),
\(\therefore \angle BAE = 10^\circ \),
\(\therefore \angle DAF = 10^\circ \),
\(\therefore \angle EAF = \angle BAD - \angle BAE - \angle DAF \)
\(= 100^\circ - 10^\circ - 10^\circ = 80^\circ \)。