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若函数\(y = \left\{ {\begin{array}{*{20}{l}} {{x^2} + 2(x⩽2)} \\ {2x(x > 2)} \end{array}} \right.\),则当函数值\(y = 8\)时,自变量\(x\)的值是\((\) \()\)
A.\( \pm \sqrt 6 \)
B.4
C.\( \pm \sqrt 6 \)或4
D.4或\( - \sqrt 6 \)
参考答案:D
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