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初中数学八年级下册(648题)


如图,在四边形\(ABCD\)中,\(AC\)\(BD\)的垂直平分线,\(E\)\(CD\)上一点,\(BE\)\(AC\)\(F\),连接\(DF\)\(\angle BEC = \angle ADF\),证明四边形\(ABCD\)是菱形

图片 7     



知识点:第十八章 平行四边形


参考答案:证明:\(\because AC\)是\(BD\)的垂直平分线,点\(F\)在\(AC\)上,

\(\therefore AB = AD\),\(BC = CD\),\(FD=FB\),

\(\because \)在\(\Delta ABF\)和\(\Delta ADF\)中,

\(\left\{ {\begin{array}{*{20}{l}} {AB = AD} \\ {FB = FD} \\ {AF = AF} \end{array}} \right.\),

\(\therefore \Delta ABF \cong \Delta ADF({\rm{SSS}})\),

\(\therefore \angle ABF = \angle ADF\),\(∠BAC=∠DAC\)

\(\because \angle BEC = \angle ADF\),

\(\therefore \angle BEC = \angle ABF\),

\(\therefore AB//CD\),

\(\therefore \angle BAC = \angle ACD\),

\(\therefore \angle DAC = \angle ACD\),

\(\therefore AD = CD\),

\(\because AB = AD\),\(BC = CD\),

\(\therefore AB = CB = CD = AD\),

\(\therefore \)四边形\(ABCD\)是菱形。

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