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初中数学八年级下册(648题)


已知:如图,在四边形\(ABCD\)中,\(AB = AD\)\(BD\)平分\(\angle ABC\)\(\angle A = \angle C\)求证:四边形\(ABCD\)为菱形

图片 15    



知识点:第十八章 平行四边形


参考答案:证明:
\(\because BD\)平分\(\angle ABC\),
\(\therefore \angle ABD = \angle CBD\),
\(\because \)在\(\Delta ABD\)和\(\Delta CBD\)中\(\left\{ {\begin{array}{*{20}{l}}
{\angle ABD = \angle CBD} \\
{\angle A = \angle C} \\
{BD = BD}
\end{array}} \right.\),
\(\therefore \Delta ABD≌\Delta CBD(AAS)\),
\(\therefore AB = BC\),\(AD = DC\),
\(\because AB = AD\),
\(\therefore AB = BC = DC = AD\),
\(\therefore \)四边形\(ABCD\)是菱形。

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