初中数学八年级下册（648题）

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知识点：第十八章　平行四边形

参考答案：解：
\(\because \)四边形\(ABCD\)是菱形，\(BD = 10\)，\(AC = 24\)，
\(\therefore AB = BC = CD = AD\)，\(OA = \frac{1}{2}AC = 12\)，\(OB = \frac{1}{2}BD = 5\)，\(AC \bot BD\)，
\(\therefore \angle AOB = 90^\circ \)，
\(\therefore AB = \sqrt {O{A^2} + O{B^2}} = \sqrt {{{12}^2} + {5^2}} = 13\)，
\(\therefore \)菱形的周长\( = 4AB = 52\)．