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初中数学八年级下册（648题）
如图，在菱形
知识点：第十八章 平行四边形
参考答案：证明：\(\because \)四边形\(ABCD\)是菱形，\(\therefore AB = AD = BC = CD\)，\(\angle B = \angle D\)，在\(\Delta ABE\)和\(\Delta ADF\)中，\(\left\{ {\begin{array}{*{20}{l}}
{\angle BAE = \angle DAF} \\
{AB = AD} \\
{\angle B = \angle D}
\end{array}} \right.\)，\(\therefore \Delta ABE \cong \Delta ADF(ASA)\)，\(\therefore BE = DF\)，\(\therefore BC - BE = CD - DF\)，即\(CE = CF\)。