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如图,矩形\(ABCD\)中,连接\(AC\),延长\(BC\)至点\(E\),使\(BE = AC\),连接\(DE\).若\(\angle E = 70^\circ \),则\(\angle ACB\)的度数是( )
A.\(40^\circ \)
B.\(45^\circ \)
C.\(50^\circ \)
D.\(60^\circ \)
参考答案:A
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