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为了研究钟表秒针针尖的运动变化规律,建立如图所示的平面直角坐标系,设秒针针尖位置为点
A.\(y=2\sin {\left ( {-\frac {\pi } {30}t+\frac {\pi } {3}} \right )}\)
B.\(y=-\sin {\left ( {-\frac {\pi } {60}t-\frac {\pi } {3}} \right )}\)
C.\(y=\sin {\left ( {-\frac {\pi } {30}t+\frac {\pi } {6}} \right )}\)
D.\(y=\cos {\left ( {\frac {\pi } {30}t+\frac {\pi } {6}} \right )}\)
参考答案:D