“微信扫一扫”进入题库练习及模拟考试
已知函数
求
参考答案:令\(2k\pi -\frac {\pi } {2}\leq 2x+\frac {\pi } {6}\leq 2k\pi +\frac {\pi } {2}\),求得\(k\pi -\frac {\pi } {3}\leq x\leq k\pi +\frac {\pi } {6},\left ( {k\in Z} \right )\),
可得函数的增区间为\(\left [ {k\pi -\frac {\pi } {3},k\pi +\frac {\pi } {6}} \right ],\left ( {k\in Z} \right )\).
解析: