“微信扫一扫”进入题库练习及模拟考试
已知
化简
参考答案:\(f(\alpha ) = \frac{{\sin (\pi - \alpha )\cos (2\pi - \alpha )\sin ( - \alpha + \frac{{3\pi }}{2})}}{{\cos ( - \alpha - \pi )\cos ( - \alpha + \frac{{7\pi }}{2})}} = \frac{{\sin \alpha \cos \alpha ( - \cos \alpha )}}{{ - \cos \alpha ( - \sin \alpha )}} = - \cos \alpha \)
解析: