“微信扫一扫”进入题库练习及模拟考试
已知
求
参考答案:\(\because \cos {α=-\frac {4} {5}}\),且\(\tan \alpha > 0\),则\(\alpha \)为第三象限角,
\(\therefore \sin \alpha = - \sqrt {1 - co{s^2}\alpha } = - \sqrt {1 - {{( - \frac{4}{5})}^2}} = - \frac{3}{5}\),\(\therefore \tan \alpha = \frac{{\sin \alpha }}{{\cos \alpha }} = \frac{3}{4}\);
解析: