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高中数学必修 第一册(648题)


已知\(\cos \alpha = - \frac{4}{5}\),且\(\tan \alpha > 0\)



\(\tan \alpha \)的值;




知识点:第五章 三角函数


参考答案:\(\because \cos {α=-\frac {4} {5}}\),且\(\tan \alpha > 0\),则\(\alpha \)为第三象限角,

\(\therefore \sin \alpha = - \sqrt {1 - co{s^2}\alpha } = - \sqrt {1 - {{( - \frac{4}{5})}^2}} = - \frac{3}{5}\),\(\therefore \tan \alpha = \frac{{\sin \alpha }}{{\cos \alpha }} = \frac{3}{4}\);


解析:



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