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高中数学必修 第一册(648题)



已知 \(f(\alpha ) = \frac{{\cos (\frac{\pi }{2} + \alpha )\sin (\alpha - \frac{\pi }{2})}}{{\cos ( - \pi - \alpha )\tan (\pi - \alpha )}}\) ,求 \(f\left ( {\frac {2017\pi } {3}} \right )\).




知识点:第五章 三角函数


参考答案:\(\because f\left ( {α} \right )=\frac {\cos {\left ( {\frac {\pi } {2}+α} \right )\sin {\left ( {α-\frac {\pi } {2}} \right )}}} {\cos {\left ( {-\pi -α} \right )\tan {\left ( {\pi -α} \right )}}}=\frac {\left ( {-\sin {α}} \right )\left ( {-\cos {α}} \right )} {\left ( {-\cos {α}} \right )\left ( {-\tan {α}} \right )}=\cos {α}\)

\(\therefore f\left ( {\frac {2017\pi } {3}} \right )=\cos {\left ( {672\pi +\frac {\pi } {3}} \right )}=\cos {\frac {\pi } {3}}=\frac {1} {2}\)

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