高中数学必修 第一册（648题）

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知识点：第四章 指数函数与对数函数

参考答案：\( \because 0>{\mathrm{log}}_{0.2}3>{\mathrm{log}}_{0.2}4\)
\( \therefore \frac{1}{{\mathrm{log}}_{0.2}3}<\frac{1}{{\mathrm{log}}_{0.2}4}\)
即 \( {\mathrm{log}}_{3}0.2<{\mathrm{log}}_{4}0.2\)