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计算 \((1 + {2^{ - \tfrac{1}{{32}}}})(1 + {2^{ - \tfrac{1}{{16}}}})(1 + {2^{ - \tfrac{1}{8}}})(1 + {2^{ - \tfrac{1}{4}}})(1 + {2^{ - \tfrac{1}{2}}})\)=___（结果不必化简）.
参考答案：\(\frac{1}{{2(1 - {2^{ - \tfrac{1}{{32}}}})}}\)
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