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已知定义在\({\rm{R}}\)上的函数\(f\left( x \right)\)在\(\left( { - \infty ,3} \right]\)上单调递增,且\(f\left( {x + 3} \right)\)为偶函数,则不等式\(f\left( {x + 1} \right) > f\left( {2x} \right)\)的解集为( )
A.\(\left( {1,\frac{5}{3}} \right)\)
B.\(\left( { - \infty ,1} \right) \cup \left( {\frac{5}{3}, + \infty } \right)\)
C.\(\left( { - \infty ,1} \right)\)
D.\(\left( {1, + \infty } \right)\)
参考答案:B
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