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已知\(f\left( x \right)\)是定义在\({\mathbf{R}}\)上的奇函数﹐且满足\(f\left( {2 + x} \right) = f\left( {2 - x} \right)\)，当\(x \in \left( {0,2} \right]\)时，\(f\left( x \right) = {x^2} + a\)，若\(f\left( {2022} \right) = 0\)，则\(a = \)___.
参考答案：\( - 4\)
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