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已知函数
A.\(f(2020)=0\)
B.方程\(f\left ( {x} \right )=\frac {1} {4}x-1\)有三个实数根
C.当\(x∈[4,6)\)时,\(f(x)=|x-5|-1\)
D.若函数\(y=f(x)-t\)在\((-∞,6)\)上有8个零点\( {x}-{i}\)(i=1,2,3,…,8),则\({x}-{1}f\left ( {{x}-{1}} \right )+{x}-{2}f\left ( {{x}-{2}} \right )+\cdots +{x}-{8}f\left ( {{x}-{8}} \right )\)的取值范围为\((-16,0)\)
参考答案:ACD