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已知\(f\left ( {\frac {1} {x-1}} \right )=x+1\),则\(f\left ( {x} \right )\)的解析式为( )
A.\(\frac {1} {x+2}\left ( {x≠-2} \right )\)
B.\(\frac {1+x} {x}\left ( {x≠0} \right )\)
C.\(\frac {1} {x}+2\left ( {x≠0} \right )\)
D.\(\frac {1} {x}-1\left ( {x≠0} \right )\)
参考答案:C
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