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已知\(f\left ( {\frac {1} {x}} \right )=\frac {1} {x+1}\),则\(f\left ( {x} \right )\)的解析式为( )
A.\(f\left ( {x} \right )=\frac {1} {1+x}\)
B.\(f\left ( {x} \right )=\frac {1+x} {x}\)
C.\(f\left ( {x} \right )=\frac {x} {1+x}\left ( {x≠0} \right )\)
D.\(f\left ( {x} \right )=x+1\)
参考答案:C
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