设函数\(f\left ( {x+1} \right )=\frac {4} {1-x}\)，若\(f\left ( {a} \right )=2\)，则实数\

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设函数\(f\left ( {x+1} \right )=\frac {4} {1-x}\)，若\(f\left ( {a} \right )=2\)，则实数\(a=\)___.

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