高中数学必修 第一册（648题）

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知识点：第二章 一元二次函数、方程和不等式

参考答案：\(a < 0\)时，不等式:\(\frac{{ax - 1}}{{x - 2}} > \frac{a}{2}\)的解集为\(\left\{ {x\left| {\frac{2}{a} - 2 \leqslant x < 2} \right.} \right\}\)；当\(a = 0\)时，不等式:\(\frac{{ax - 1}}{{x - 2}} > \frac{a}{2}\)的解集为\(\left\{ {x\left| {x < 2} \right.} \right\}\)；当\(0 < a < \frac{1}{2}\)时，不等式:\(\frac{{ax - 1}}{{x - 2}} > \frac{a}{2}\)的解集为\(\left\{ {x\left| {x \geqslant \frac{2}{a} - 2或x < 2} \right.} \right\}\)；当\(a = \frac{1}{2}\)时，不等式:\(\frac{{ax - 1}}{{x - 2}} > \frac{a}{2}\)的解集为\(\left\{ {x\left| {x \ne 2} \right.} \right\}\)；当\(a > \frac{1}{2}\)时，不等式:\(\frac{{ax - 1}}{{x - 2}} > \frac{a}{2}\)的解集为\(\left\{ {x\left| {x \leqslant \frac{2}{a} - 2} \right.} \right.\)或\(\left. {x > 2} \right\}\).