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解关于\(x\)的不等式:\({x^2} - \left( {3a - 1} \right)x + 2{a^2} - 2a > 0\).
参考答案:当\(a < - 1\)时,不等式的解为\(\{ x\left| x \right\rangle a - 1\)或\(x < 2a\} \);当\(a = - 1\)时,不等式的解为\(\{ x \in {\mathbf{R}}|x \ne - 2\} \);当\(a > - 1\)时,不等式的解为\(\{ x\left| x \right\rangle 2a\)或\(x < a - 1\} \).
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