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已知函数\(f\left( x \right) = \left( {x - 1} \right)\left( {ax + 1} \right)\),其中\(a\in \text{R}\).
若不等式\(f\left( x \right) > 0\)的解集为\(\left\{ {x\left| {1 < x < 2} \right.} \right\}\),求\(a\)的值;
参考答案:\( - \frac{1}{2}\)
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