“微信扫一扫”进入题库练习及模拟考试
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参考答案:证明:充分性:\(\because a - b + c = 0\),\(\therefore c = b - a\),代入方程\(a{x^2} + bx + c = 0\)得\(a{x^2} + bx + b - a = 0\),即\(\left( {x + 1} \right)\left( {ax - a + b} \right) = 0\).\(\therefore \)关于\(x\)的方程\(a{x^2} + bx + c = 0\)有一个根为\( - 1\);
必要性:\(\because \)方程\(a{x^2} + bx + c = 0\)有一个根为\( - 1\),\(\therefore x = - 1\)满足方程\(a{x^2} + bx + c = 0\),\(\therefore a \times {1^2} + b \times \left( { - 1} \right) + c = 0\),即\(a - b + c = 0\).故关于\(x\)的方程\(a{x^2} + bx + c = 0\)有一个根是\( - 1\)的充要条件是\(a - b + c = 0\).