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高中数学必修 第一册(648题)


已知集合\(A=\left \{ {x|{x}^{2}-3x+2=0,x\in \text{R}} \right \} \),集合\(B=\left \{ {x|{x}^{2}-2\left ( {a+1} \right )x+{a}^{2}-5=0,x\in \text{R}} \right \} \)



若集合\(A\cap B=\left \{ {2} \right \} \),求实数\(a\)的值;




知识点:第一章 集合与常用逻辑用语


参考答案:\(a=5\)或\(a=-1\)

\(A=\left \{ {x|{x}^{2}-3x+2=0} \right \} =\left \{ {x|\left ( {x-1} \right )\left ( {x-2} \right )=0} \right \} =\left \{ {1,2} \right \} \)

若集合\(A\cap B=\left \{ {2} \right \} \),则\(2\in B\)且\(1∉B\),

将\(x=2\)代入方程\({x}^{2}-2\left ( {a+1} \right )x+{a}^{2}-5=0\)可得\({a}^{2}-4a-5=0\),

解得:\(a=5\)或\(a=-1\);

当\(a=5\)时,原方程可化为\({x}^{2}-12x+20=0\),解得:\(x=2\)或\(x=10\),

此时\(B=\left \{ {2,-2} \right \} \),满足\(A\cap B=\left \{ {2} \right \} \),

当\(a=-1\)时,原方程可化为\({x}^{2}-4=0\),解得:\(x=2\)或\(x=-2\),

此时\(B=\left \{ {2,-2} \right \} \),满足\(A\cap B=\left \{ {2} \right \} \),

所以\(a=5\)或\(a=-1\);

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