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集合
若
参考答案:\((-\infty ,4]\)
\(\because B\subseteq A\),∴①\(B=\varnothing \)时,\(m+1>2m-1\),解得\(m<2\);②\(B\ne \varnothing \)时,\( \left\{\begin{array}{l}m\ge 2\\ m+1\ge -3\\ 2m-1\le 7\end{array}\right.\),解得\(2\le m\le 4\),综上,实数\(m\)的取值范围为\((-∞,4]\);