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解不等式组\(\left\{ {\begin{array}{*{20}{l}} {2x + 1 < 3x + 3} \\ {x + \frac{1}{3} \leqslant \frac{{2 + x}}{3}} \end{array}} \right.\),并写出它的整数解.
参考答案:\( - 2 < x \leqslant 0.5\)整数解为\( - 1,0\)
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