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用适当的方法解下列方程组:
\(\left\{ {\begin{array}{*{20}{l}} {x - y = 1} \\ {x + 3y + z = 10} \\ {x - 2y - z = - 2} \end{array}} \right.\).
参考答案:\(\left\{ {\begin{array}{*{20}{l}} {x = 3} \\ {y = 2} \\ {z = 1} \end{array}} \right.\)
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