请阅读下列材料，解答问题：

材料：解方程组\(\left\{ {\begin{array}{*{20}{l}}
{5(x + y) - 3(x - y) = 2} \\
{2(x + y) + 4(x - y) = 6}
\end{array}} \right.\)，若设\(x + y = m\)，\(x - y = n\)，则原方程组可变形为\(\left\{ {\begin{array}{*{20}{l}}
{5m - 3n = 2} \\
{2m + 4n = 6}
\end{array}} \right.\)，用加减消元法解得\(\left\{ {\begin{array}{*{20}{l}}
{m = 1} \\
{n = 1}
\end{array}} \right.\)，所以\(\left\{ {\begin{array}{*{20}{l}}
{x + y = 1} \\
{x - y = 1}
\end{array}} \right.\)，再解这个方程组得\(\left\{ {\begin{array}{*{20}{l}}
{x = 1} \\
{y = 0}
\end{array}} \right.\)。由此可以看出，在上述解方程组过程中，把某个式子看成一个整体，用一个字母去代替它，我们把这种解方程组的方法叫换元法。

问题：请你用上述方法解方程组\(\left\{ {\begin{array}{*{20}{l}}
{\frac{{x + y}}{3} + \frac{{x - y}}{2} = 1} \\
{2(x + y) - 3x + 3y = 6}
\end{array}} \right.\)。

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